## A waitress believes the distribution of her tips has a model that is slightly skewed to the left, with a mean of $9.40 and a standard deviat

Question

A waitress believes the distribution of her tips has a model that is slightly skewed to the left, with a mean of $9.40 and a standard deviation of $6.10. She usually waits on about 60 parties over a weekend of work.

a) Estimate the probability that she will earn at least $600

P(tips from 60 parties > $600)

b) How much does she earn on the best 5% of such weekends?

The total amount that she earns on the best 5% of such weekends is at least $__

in progress
0

Math
1 month
2021-10-18T13:31:35+00:00
2021-10-18T13:31:35+00:00 1 Answer
0 views
0
## Answers ( )

Answer:a. P(tips from 60 parties > $600)=0.461

b. The total amount that she earns on the best 5% of such weekends is at least $19.43.

Step-by-step explanation:a. To earn $600 in 60 parties means $10 per party in average.

If we assume a normal distribution of tips, we can calculate the z-value and its probability for this situation:

There is a probability of 46% that she earns at least $600 over a weekend of work.

b. The best 5% of the weekends corresponds to:

This probability (5%) corresponds to a z-value of z=1.6449.

In tips, this value represents:

The total amount that she earns on the best 5% of such weekends is at least $19.43.